2x+1x^2+8=0

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Solution for 2x+1x^2+8=0 equation:


Simplifying
2x + 1x2 + 8 = 0

Reorder the terms:
8 + 2x + 1x2 = 0

Solving
8 + 2x + 1x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + 2x + -8 + x2 = 0 + -8

Reorder the terms:
8 + -8 + 2x + x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 2x + x2 = 0 + -8
2x + x2 = 0 + -8

Combine like terms: 0 + -8 = -8
2x + x2 = -8

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -8 + 1

Reorder the terms:
1 + 2x + x2 = -8 + 1

Combine like terms: -8 + 1 = -7
1 + 2x + x2 = -7

Factor a perfect square on the left side:
(x + 1)(x + 1) = -7

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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